This is the first of a twopart series about Bayesian bandit algorithms. Check out the second post here.
Let’s talk about Bayesianism. It’s developed a reputation (not entirely justified, but not entirely unjustified either) for being too mathematically sophisticated or too computationally intensive to work at scale. For instance, inferring from a Gaussian mixture model is fraught with computational problems (hierarchical funnels, multimodal posteriors, etc.), and may take a seasoned Bayesian anywhere between a day and a month to do well. On the other hand, other blunt hammers of estimation are as easy as a maximum likelihood estimate: something you could easily get a SQL query to do if you wanted to.
In this blog post I hope to show that there is more to Bayesianism than just MCMC sampling and suffering, by demonstrating a Bayesian approach to a classic reinforcement learning problem: the multiarmed bandit.
The problem is this: imagine a gambler at a row of slot machines (each machine being a “onearmed bandit”), who must devise a strategy so as to maximize rewards. This strategy includes which machines to play, how many times to play each machine, in which order to play them, and whether to continue with the current machine or try a different machine.
This problem is a central problem in decision theory and reinforcement learning: the agent (our gambler) starts out in a state of ignorance, but learns through interacting with its environment (playing slots). For more details, Cam DavidsonPilon has a great introduction to multiarmed bandits in Chapter 6 of his book Bayesian Methods for Hackers, and Tor Lattimore and Csaba Szepesvári cover a breathtaking amount of the underlying theory in their book Bandit Algorithms.
So let’s get started! I assume that you are familiar with:
 some basic probability, at least enough to know some distributions: normal, Bernoulli, binomial…
 some basic Bayesian statistics, at least enough to understand what a conjugate prior (and conjugate model) is, and why one might like them.

Python generators and the
yield
keyword, to understand some of the code I’ve written^{1}.
Dive in!
The Algorithm
The algorithm is straightforward. The description below is taken from Cam DavidsonPilon over at Data Origami^{2}.
For each round,
 Sample a random variable from the prior of bandit , for all .
 Select the bandit with largest sample, i.e. select bandit .
 Observe the result of pulling bandit , and update your prior on bandit using the conjugate model update rule.
 Repeat!
What I find remarkable about this is how dumbfoundingly simple it is! No MCMC sampling, no s to diagnose, no pesky divergences… all it requires is a conjugate model, and the rest is literally just counting.
NB: This algorithm is technically known as Thompson sampling, and is only one of many algorithms out there. The main difference is that there are other ways to go from our current priors to a decision on which bandit to play next. E.g. instead of simply sampling from our priors, we could use the upper bound of the 90% credible region, or some dynamic quantile of the posterior (as in Bayes UCB). See Data Origami^{2} for more information.
Stochastic (a.k.a. stationary) bandits
Let’s take this algorithm for a spin! Assume we have rewards which are Bernoulli distributed (this would be the situation we face when e.g. modelling clickthrough rates). The conjugate prior for the Bernoulli distribution is the Beta distribution (this is a special case of the BetaBinomial model).
Here, pull
returns the result of pulling on the arm
‘th bandit, and
make_bandits
is just a factory function for pull
.
The bayesian_strategy
function actually implements the algorithm. We only need
to keep track of the number of times we win and the number of times we played
(num_rewards
and num_trials
, respectively). It samples from all current
np.random.beta
priors (where the original prior was a , which is symmetrix about 0.5 and explains the oddlooking a=2+
and
b=2+
there), picks the np.argmax
, pull
s that specific bandit, and updates
num_rewards
and num_trials
.
I’ve omitted the data visualization code here, but if you want to see it, check out the Jupyter notebook on my GitHub
Generalizing to conjugate models
In fact, this algorithm isn’t just limited to Bernoullidistributed rewards: it will work for any conjugate model! Here I implement the GammaPoisson model (that is, Poisson distributed rewards, with a Gamma conjugate prior) to illustrate how extensible this framework is. (Who cares about Poisson distributed rewards, you ask? Anyone who worries about returning customers, for one!)
Here’s what we need to change:
 The rewards distribution on line 5 (in practice, you don’t get to pick this, so technically there’s nothing to change if you’re doing this in production!)
 The sampling from the prior on lines 17–18
 The variables you need to keep track of and update rule on lines 12–13 and 24–25.
Without further ado:
This really demonstrates how lean and mean conjugate models can be, especially considering how much of a pain MCMC or approximate inference methods would be, compared to literal counting. Conjugate models aren’t just textbook examples: they’re (gasp) actually useful!
Generalizing to arbitrary rewards distributions
OK, so if we have a conjugate model, we can use Thompson sampling to solve the multiarmed bandit problem. But what if our rewards distribution doesn’t have a conjugate prior, or what if we don’t even know our rewards distribution?
In general this problem is very difficult to solve. Theoretically, we could place some fairly uninformative prior on our rewards, and after every pull we could run MCMC to get our posterior, but that doesn’t scale, especially for the online algorithms that we have in mind. Luckily a recent paper by Agrawal and Goyal^{3} gives us some help, if we assume rewards are bounded on the interval (of course, if we have bounded rewards, then we can just normalize them by their maximum value to get rewards between 0 and 1).
This solutions bootstraps the first BetaBernoulli model to this new situation. Here’s what happens:
 Sample a random variable from the (Beta) prior of bandit , for all .
 Select the bandit with largest sample, i.e. select bandit .
 Observe the reward from bandit .
 Observe the outcome from a Bernoulli trial with probability of success .
 Update posterior of with this observation .
 Repeat!
Here I do this for the logitnormal distribution (i.e. a random variable whose
logit is normally distributed). Note that np.expit
is the inverse of the logit
function.
Final Remarks
None of this theory is new: I’m just advertising it . See Cam DavidsonPilon’s great blog post about Bayesian bandits^{2} for a much more indepth treatment, and of course, read around papers on arXiv if you want to go deeper!
Also, if you want to see all the code that went into this blog post, check out the notebook here.
This is the first of a twopart series about Bayesian bandit algorithms. Check out the second post here.

I’ve hopped on board the functional programming bandwagon, and couldn’t help but think that to demonstrate this idea, I didn’t need a framework, a library or even a class. Just two functions! ↩

DavidsonPilon, Cameron. “MultiArmed Bandits.” DataOrigami, 6 Apr. 2013, dataorigami.net/blogs/napkinfolding/79031811multiarmedbandits ↩ ↩^{2} ↩^{3}

arXiv:1111.1797 [cs.LG] ↩
Share on
Twitter Facebook LinkedIn Reddit EmailWant to get my blog posts by email?
Subscribe to my mailing list to follow my blog!
You'll only get emailed when I publish new posts.